Matemáticas, pregunta formulada por alba5375, hace 5 meses

me ayudan por favor)? ✌​

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Contestado por JoseMauel369
14

Respuesta:

Explicación paso a paso:

Para este ejercicio: solo sustituimos los valores, ya que tenemos la función:

N_{(s)} =2.25s^{2}-9s+11

Para N=0, tenemos:

N_{(0)} =2.25(0)^{2}-9(0)+11\\\\N_{(0)}=2.25(0)-0+11\\\\N_{(0)} =0+11\\\\N_{(0)} =11

Para N=1, tenemos:

N_{(1)} =2.25(1)^{2}-9(1)+11\\\\N_{(1)}=2.25(1)-9+11\\\\N_{(1)} =2.25-9+11\\\\N_{(1)} =13.25-9\\\\N_{(1)} =4.25

Para N=2, tenemos:

N_{(2)} =2.25(2)^{2}-9(2)+11\\\\N_{(2)}=2.25(4)-18+11\\\\N_{(2)} =9-18+11\\\\N_{(2)} =20-18\\\\N_{(2)} =2

Para N=3, tenemos:

N_{(3)} =2.25(3)^{2}-9(3)+11\\\\N_{(3)}=2.25(9)-27+11\\\\N_{(3)} =20.25-27+11\\\\N_{(3)} =31.25-27\\\\N_{(3)} =4.25

Para N=4, tenemos:

N_{(4)} =2.25(4)^{2}-9(4)+11\\\\N_{(4)}=2.25(16)-36+11\\\\N_{(4)} =36-36+11\\\\N_{(4)} =47-36\\\\N_{(4)} =11

Para N=5, tenemos:

N_{(5)} =2.25(5)^{2}-9(5)+11\\\\N_{(5)}=2.25(25)-45+11\\\\N_{(5)} =56.25-45+11\\\\N_{(5)} =67.25-45\\\\N_{(5)} =22.25

Para N=10, tenemos:

N_{(10)} =2.25(10)^{2}-9(10)+11\\\\N_{(10)}=2.25(100)-90+11\\\\N_{(10)} =225-90+11\\\\N_{(10)} =236-90\\\\N_{(10)} =146

Para N=100, tenemos:

N_{(100)} =2.25(100)^{2}-9(100)+11\\\\N_{(100)}=2.25(10000)-900+11\\\\N_{(100)} =22500-900+11\\\\N_{(100)} =22511-900\\\\N_{(100)} =21611


JoseMauel369: Espero te sirva. Dame coronita, por favor
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