Question

Me ayudan plissssssss......

Answer 1

Respuesta:

$x=\frac{\sqrt{231}}{9},\:x=-\frac{\sqrt{231}}{9}$

Explicación paso a paso:

$\frac{\left(x^2-\frac{5}{9}\right)}{4-\sqrt{\frac{25}{81}}}=3-7\times \frac{1}{3}$

$\frac{31\left(x^2-\frac{5}{9}\right)}{4-\sqrt{\frac{25}{81}}}=31\times \:3-31\times \:7\times \frac{1}{3}$

$9x^2-5+5=\frac{62}{3}+5$

$9x^2=\frac{77}{3}$

$x^2=\frac{77}{27}$

$=\sqrt{\frac{77}{27}},\:x=-\sqrt{\frac{77}{27}}$

$\mathrm{Aplicar\:la\:siguiente\:propiedad\:de\:los\:radicales:}\:\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$=\frac{\sqrt{77}}{\sqrt{27}}$

$=\frac{\sqrt{77}}{3\sqrt{3}} =\frac{\sqrt{231}}{9}$

$+ \frac{\sqrt{231}}{9} \vee \: -\frac{\sqrt{231}}{9}$