Question

me ayudan plis qwq! te doy 5 estrellas

$(x + y)^{8} =$
$(2m + n) ^{5} =$
$(7a + 2n)^{4} =$
$(3q + 2p)^{3} =$
$(m - 7n)^{4} =$
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Answer 1

(x+y)⁸= x⁸+ 8x⁷ y +28x⁶ y ² + 56x⁵ y³ + 70x⁴ y⁴ + 56x³ y⁵ + 28x² y⁶ + 8xy⁷ + y⁸

(2m+n)⁵= 32m⁵ + 80m⁴n + 80m³n² + 40m²n³ + 10mn⁴ + n⁵

(7a+2n)⁴= 2401a⁴ + 2744a³n + 1176a²n² + 224an³ + 16n⁴

(3q+2p)³= 27q³ + 54pq² + 36p²q + 8p³

(m-7n)⁴= m³ - 21m²n + 147mn² - 343n³

espero te sirva