Question

me ayudan plis paso a paso :]​

Answer 1

$\bold{\sqrt{\sqrt{\frac{81}{16}}}+\left(\frac{2}{4}+\frac{1}{2}\right)^2+\frac{2}{3}}$

$\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \sqrt{a}=a^{\frac{1}{2}}$

$\bold{=\left(\frac{81}{16}\right)^{\frac{1}{2}\cdot \frac{1}{2}}}$

$\bold{=\left(\frac{81}{16}\right)^{\frac{1}{4}}}$

$\bold{=\frac{\sqrt[4]{81}}{2}}$

$\bold{=\frac{3}{2}}$

$\bold{\frac{1}{2}+\frac{1}{2}}$

$\bold{=\frac{1+1}{2}}$

$\bold{=\frac{2}{2}}$

$\bold{=1}$

$\bold{=\frac{3}{2}+1+\frac{2}{3}}$

$\mathrm{Convertir\:a\:fraccion}:\quad \:1=\frac{1}{1}$

$\bold{=\frac{1}{1}+\frac{3}{2}+\frac{2}{3}}$

$\bold{=\frac{6}{6}+\frac{9}{6}+\frac{4}{6}}$

$\mathrm{Aplicar\:las\:propiedades\:de\:las\:fracciones}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}$

$\bold{=\frac{6+9+4}{6}}$

$\mathrm{Sumar:}\:6+9+4=19$

$\boxed{\bold{=\frac{19}{6}}}$