Question

me ayudan plis gracias:D

Answer 1

Explicación paso a paso:

$x { {}^{3} - 2x {}^{3} }^{} - x + 1$

P(0)=

$(0) {}^{3} - 3(0) {}^{2} - (0) - 1$

$= - 1$

p(1)

$(1) {}^{3} - 3(1) {}^{2} - (1) - 1$

$1 - 3 - 1 - 1$

$= - 2$

p(-1)

$( - 1) {}^{3} - 3( - 1) {}^{2} - ( - 1) - 1$

=

$= - 1 - 3 + 1 - 1$

$= - 2$

p(-2)

$( - 2) {}^{3} - 3( - 2) {}^{2} - ( - 2) - 1$

= -8-3(4)+2-1

= -8-12+2-1

= -19

P(1/2)

$( \frac{1}{2} ) {}^{3} - 3( \frac{1}{2} ) {}^{2} - ( \frac{1}{2} ) - 1$

$\frac{1}{8} - \frac{3}{4} - \frac{1}{2} - 1$

$\frac{1}{8} - \frac{6}{8} - \frac{4}{8} - \frac{8}{8}$

= -17/8