Question

ME AYUDAN PLIS (5+5)x(2/5 +3/9 x 55) +4/6 x 6/15 =

Answer 1

Respuesta:

187,6

Explicación paso a paso:

(5+5)x(2/5 +3/9 x 55) +4/6 x 6/15

10 × ( $\frac{2}{5}$ + $\frac{3}{9}$×55) + $\frac{4}{6} .\frac{6}{15}$

10 × ( $\frac{2}{5}$ + $\frac{55}{3}$ ) + $\frac{4}{15}$

10 × ( $\frac{6+275}{15}$) + $\frac{4}{15}$

10 × $\frac{281}{15}$ + $\frac{4}{15}$

$\frac{2810}{15}$ + $\frac{4}{15}$

$\frac{2814}{15}$

187,6

Answer 2

Respuesta:

$\mathrm{El\:resultado\:es:}\:$  $\frac{938}{5}.$

Explicación paso a paso:

$\left(5+5\right)\times \left(2/5\:+3/9\:\times \:\:55\right)\:+4/6\:\times \:\:6/15$

$\left(5+5\right)\left(\frac{2}{5}+\frac{3}{9}\times \:55\right)+\frac{4}{6}\times \frac{6}{15}$

$10\left(\frac{2}{5}+\frac{55}{3}\right)+\frac{4}{6}\times \frac{6}{15}$

$10\times \frac{281}{15}+\frac{4}{6}\times \frac{6}{15}$

$\frac{281\times \:10}{15}+\frac{4\times \:6}{6\times \:15}$

$\frac{2810}{15}+\frac{4}{15}$

$\frac{2814}{15}$

$\mathrm{Eliminar\:el\:termino\:comun:}\:3$

$\frac{938}{5}$