Question

me ayudan con esto es para recuperar

Answer 1

10) $\frac{x}{3}- \frac{x-2}{4}=1$

$\frac{4x-3x+6}{12}=1$

x + 6 = 1(12)

x = 12 - 6

x = 6

11) $\frac{-2}{7}$x + 2 = x - 3

$\frac{-2x+14}{7}=x-3$

-2x + 14 = 7(x-3)

-2x + 14 = 7x - 21

-2x - 7x = - 21 - 14

-9x = - 35

x = $\frac{-35}{-9}$

x = $\frac{35}{9}$

12) 49$x^{4}-109 x^{2} y^{2}+36 y^{4}$

49$x^{4} - 109 x^{2} y^{2}+25 x^{2} y^{2}+36 y^{4} -25x^{2} y^{2}$

49$x^{4}-84 x^{2} y^{2}+36 y^{4} -25x^{2} y^{2}$

(7$x^{2} + 5xy - 6 y^{2})(7 x^{2}  - 5xy - 6y^{2})$

13) 121$y^{4}-133 y^{2} z^{4}+36 z^{8}$

121$y^{4}-133 y^{2} z^{4}+ y^{2} z^{4}+36 z^{8}- y^{2} z^{4}$

121$y^{4}-132 y^{2} z^{4}+36 z^{8}- y^{2} z^{4}$

(11$y^{2}+y z^{2}-6 z^{4})(11 y^{2}-y z^{2}-6 z^{4})$

14) ($x^{4}-2)( x^{4}+5)$

$x^{8}+3 x^{4}-10$

15) $(2xy+4z)^{3}$

8$x^{3} y^{3}+3.4 x^{2} y^{2}.4z+3.2xy.16 z^{2}+64 z^{3}$

$8x^{3} y^{3}+48 x^{2} y^{2}z+96xy z^{2}+64 z^{3}$