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Solve for x:
(x^2-2 x+3)/(x^3+3) = 0
Multiply both sides by x^3+3:
x^2-2 x+3 = 0
Subtract 3 from both sides:
x^2-2 x = -3
Add 1 to both sides:
x^2-2 x+1 = -2
Write the left hand side as a square:
(x-1)^2 = -2
Take the square root of both sides:
x-1 = i sqrt(2) or x-1 = -i sqrt(2)
Add 1 to both sides:
x = 1+i sqrt(2) or x-1 = -i sqrt(2)
Add 1 to both sides:
Answer: |
| x = 1+i sqrt(2) or x = 1-i sqrt(2)
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