Question

me ayudan
(con el procedimiento) porfavor​

Answer 1

${(5 + 9 + 18)}^{0} + {10}^{4} \div (84 - 35 + 1) ^{2} - \sqrt[3]{64} = \\ 1 + 10000 \div (49 + 1)^{2} - 4 = \\ 1 + 10000 \div {50}^{2} - 4 = \\ 1 + 10000 \div 2500 - 4 = \\ 1 + 4 - 4 = \\ 5 - 4 = \\ 1$

${(6 + 4)}^{3} - (50 - 23 + 3) ^{2} - (100 - 21) ^{1} \\ {10}^{3} - (27 + 3) ^{2} - {79}^{1} \\ 1000 - {30}^{2} - 79 = \\ 1000 - 900 - 79 = \\ 100 - 79 = \\ 21$