Question

Me ayudan a resolverlas plis con comprobación plis ​

Answer 1

Respuesta:

6x - 7 = 2x + 5

6x - 2x = 5 + 7

4x = 12

x = 12/4

x = 3

COMPROBAMOS :

18 - 7 = 6 + 5

11 = 11

.............................................

2x + 5 = 3x + 3

5 - 3 = 3x - 2x

2 = x

COMPROBAMOS:

4 + 5 = 6 + 3

9 = 9

..........................................

2x + 6 = x + 1

6 - 1 = x - 2x

5 = -x

x = -5

COMPROBAMOS:

-10 + 6 = -5 + 1

-4‬ = -4

Answer 2

a) 6x - 7 = 2x + 5

6x - 2x = 5 + 7

4x = 12

x = 12/4

x = 3

COMPROBAMOS :

18 - 7 = 6 + 5

11 = 11

.............................................

b) 2x + 5 = 3x + 3

  2x - 3x = 3 - 5

  -x = 3 -5

  -x = -2 Se cambia los signos en ambos miembros

   x = 2

COMPROBAMOS:

2(2) + 5 = 3(2) + 3

4 + 5 = 6 + 3

9 = 9

..........................................

c) 2x + 6 = x + 1

6 - 1 = x - 2x

5 = -x

x = -5

COMPROBAMOS:

-10 + 6 = -5 + 1

-4‬ = -4

..........................................

d)  $\frac{1}{3}+5x = \frac{4}{3}$

   $5x = \frac{4}{3} -\frac{1}{3}$

  $5x = \frac{4-1}{3}$

  $5x = \frac{3}{3}$

  5x = 1

   x = $\frac{1}{5}$

  COMPROBAMOS:

  $\frac{1}{3} + 5( \frac{1}{5} ) = \frac{4}{3}$   Desaparece $5(\frac{}{5} )$

  $\frac{1}{3} + 1 = \frac{4}{3}$

  $\frac{1+3}{3} = \frac{4}{3}$

  $\frac{4}{3} = \frac{4}{3}$

..........................................

e) 2x + 1 = $\frac{5}{2}$

  $2x = \frac{5}{2} -1$

  $2x = \frac{5 -2}{2}$

 $2x = \frac{3}{2}$

 $2x : 2=\frac{3}{2} :2$

 $x=\frac{3}{2} : 2$

$x=\frac{3}{2} X \frac{1}{2}$

$x= \frac{3}{4}$

COMPROBAMOS:

$2(\frac{3}{4}) +1=\frac{5}{2}$       Simplifica    $2 (\frac{}{4})$

$\frac{3}{2} + 1=\frac{5}{2}$

$\frac{3+2}{2}$ = $\frac{5}{2}$

$\frac{5}{2} = \frac{5}{2}$

SI TE SIRVIO DAME CORONA