Question

me ayudan a resolverlas
1. (a²-2)³=
2. (3y+5)³=
3. (3+3z)³=
4. (3-a)³=
Porfavor doy cornita ​

Answer 1

Respuesta:

$(a^{2} -2)^{3}=a^6-6a^4+12a^2-8$

$\left(3y+5\right)^3=27y^3+135y^2+225y+125$

$\left(3+3z\right)^3=27+81z+81z^2+27z^3$

$\left(3-a\right)^3=27-27a+9a^2-a^3$

Buen día

Answer 2

Respuesta:

$( {a}^{2} - 2 )^{3} \\ ( {a}^{2} )^{3} -( {2} )^{3} - 3( {a}^{2})(2)( {a}^{2} - 2) \\ {a}^{6} - 8 - 6 {a}^{2} ( {a}^{2} - 2) \\ {a}^{6} - 8 - 6 {a}^{4} - 12 {a}^{2} \\ {a}^{6} - 6 {a}^{4} - 12 {a}^{2} - 8$

Explicación paso a paso:

$(3y + 5) ^{3} \\ 27 {y}^{3} + 125 + 45y(3y + 5) \\ 27 {y}^{3} + 135 {y}^{2} + 225y + 125$

$(3 - a)^{3} \\ 27 - {a}^{3} - 9a(3 - a) \\ - {a}^{3} + {9a}^{2} - 27a + 27$