Question

Me ayudan a realizar esto por favor

Answer 1

$\frac{8}{12} = \frac{y - 1}{6 } \\ 4 = y - 1 \\ y = 5 \\ \frac{4}{6} = \frac{x + 1}{12} \\ 8 = x + 1 \\ x = 7$

$\frac{10}{t - 2} = \frac{15}{12} \\ \frac{2}{t - 2} = \frac{1}{4} \\ 8 = t - 2 \\ t = 10 \\ \frac{10}{4} = \frac{15}{u + 3 } \\ \frac{1}{2} = \frac{3}{u + 3} \\ 6 = u + 3 \\ u = 3$

$\frac{12}{8 } = \frac{2x - 1}{6} \\ 2 \times - 1 = 9 \\ \times = 5 \\ \frac{2y + 4}{8} = \frac{7.5}{6} = \frac{75}{60} = \frac{5}{4} \\ 2y + 4 = 10 \\ y = 3$