Question

matrices, ayudaaa con el b y c​

Answer 1

Respuesta:

Matrices

Explicación paso a paso:

$A=\left[\begin{array}{ccc}0&4&-2\\6&2&8 \end{array}\right]$

$B=\left[\begin{array}{ccc}-3&6&9\\12&-6&0 \end{array}\right]$

$C=\left[\begin{array}{ccc}0&-1&0\\1&-1&2 \end{array}\right]$

Hallar:$\frac{1}{2}A-(\frac{1}{3} B+C)=$

$\frac{1}{2}A-(\frac{1}{3} B+C)=\frac{1}{2}\left[\begin{array}{ccc}0&4&-2\\6&2&8 \end{array}\right]-(\frac{1}{3}\left[\begin{array}{ccc}-3&6&9\\12&-6&0 \end{array}\right]+\left[\begin{array}{ccc}0&-1&0\\1&-1&2 \end{array}\right])$

=$\left[\begin{array}{ccc}0&2&-1\\3&1&4 \end{array}\right]-(\left[\begin{array}{ccc}-1&2&3\\4&-2&0 \end{array}\right]+\left[\begin{array}{ccc}0&-1&0\\1&-1&2 \end{array}\right])$

$=\left[\begin{array}{ccc}0&2&-1\\3&1&4 \end{array}\right]-(\left[\begin{array}{ccc}-1&1&3\\5&-3&2 \end{array}\right])$

$=\left[\begin{array}{ccc}1&1&-4\\-2&4&2 \end{array}\right]$