Question

matematicas ayuda por fa

Answer 1

Explicación paso a paso:

a)

$\frac{ \sqrt[6]{128} }{ \sqrt[6]{16} } = \sqrt[6]{ \frac{128}{16} } = \sqrt[6]{8} = \sqrt[6]{ {2}^{3} } = \sqrt[6]{ { \sqrt{2} }^{6} } = \sqrt{2}$

b)

$\frac{ \sqrt{6} }{ \sqrt{2} } = \sqrt{ \frac{6}{2} } = \sqrt{3}$

c)

$\frac{ \sqrt{16} }{ \sqrt{8} } = \sqrt{ \frac{16}{8} } = \sqrt{2}$

d)

$\frac{ \sqrt{448} }{ \sqrt{14} } = \sqrt{ \frac{448}{14} } = \sqrt{32} = \sqrt{ {2}^{5} } = \sqrt{ {2}^{4} \times 2} = \sqrt{ {2}^{4} } \times \sqrt{2} = 4 \sqrt{2}$

e)

$\frac{3 \sqrt{16} }{ \sqrt{8} } = \frac{3 \sqrt{8} \sqrt{2} }{ \sqrt{8} } = 3 \sqrt{2}$