Matemáticas, pregunta formulada por jesramata, hace 1 año

m.c.m y m.c.d de estos numeros (6,9,12) (75,90,105) (32,40,48) (40,180,760)

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Contestado por marianna92001
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m.c.m ( 6,9,12) ( 75,90,105) ( 32,40, 48) (40,180,760)

6/2            9/3              12/2                   m.c.m (6,9,12)

3/3            3/3               6/2                    6 = 2x3

1                1                 3/3                    9 = 3 a la 2

                                        1                    12 = 2 a la 2 x 3

                                                              2 x 2 x 3 x 3 = 36 


75/5               90/2             105/5          m.c.m (75, 90,105)            

15/5               45/5              21/3           75 = 5 a la 2 x 3

3/3                  9/3                7/7            90 = 2 x 5 x 3

1                     3/3                 1              105 = 5 x 3 x 7

                        1                                    5 x 5 x 3 x 2 x 7 = 1050


32/2             40/2              48/2             m.c.m (32,40,48)

16/2             20/2              24/2             32 = 2 a la 5

8/2               10/2              12/2             40 = 2 a la 3 x 5

4/2                5/5                 6/2             48 = 2 a la 4 x 3

2/2                 1                   3/3               2x2x2x2xz2x5x3 = 480


40/2              180/2           760/2              m.c.m ( 40, 180, 760)

20/2                90/2           380/2              40 = 2 a la 3 x 5

10/2                45/5           190/2              90 = 2 x 5 x 3 a la 2

5/5                   9/3             95/5               760 = 2 a la 3 x 5 x 19 

1                      3/3             19/19             2x2x2x5x3x3x19 = 6840

1                       1                 1

             

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