Question

M.C.D. con procedimiento



c. M.C.D. (9, 12, 15) =

d. M.C.D. (12, 18, 42) =

Answer 1

$c)9 = {3}^{2} \\ 12 = {2}^{2} \times 3 \\ 15 = 3 \times 5 \\ M.C.D. (9, 12, 15) =3$

$d)12 = {2}^{2} \times 3 \\ 18 = 2 \times {3}^{2} \\ 42 = 2 \times 3 \times 7 \\ M.C.D. (12, 18, 42) =2 \times 3 = 6$