Matemáticas, pregunta formulada por felipe4567, hace 1 año

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Contestado por lilipoei
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1)

 \frac{7}{10}  \times  \frac{42}{3}  =  \frac{7 \times 42}{10 \times 3}  =  \frac{294}{30}

 \frac{294}{30}  \times  \frac{12}{3}  =  \frac{294 \times 12}{30 \times 3}  =  \frac{3528}{90}  =

 \frac{196}{5}

2)

 \frac{7}{10}  \times  \frac{6}{2}  \times  \frac{9}{3 }  =  \frac{7 \times 6}{10 \times 2}  =  \frac{42}{20}

 \frac{42}{20}  \times  \frac{9}{3}  =  \frac{42 \times 9}{20 \times 3}  =  \frac{378}{60}

 \frac{63}{10}

3)

 \frac{2}{4}  -  \frac{1}{7}  +  \frac{1}{2}  =  \frac{7 \times 2 - 4 \times 1}{4 \times 7}  =  \frac{10}{16}

 \frac{10}{16}  +  \frac{1}{2}  =  \frac{10 \times 2 + 16 \times 1}{16 \times 2}  =  \frac{20 + 16}{32}

 \frac{36}{32}  =  \frac{9}{8}

4)

 \frac{18}{11}  \times  \frac{3}{5}  \times  \frac{9}{3}  =  \frac{18 \times 3}{11 \times 5}  =  \frac{54}{55}

 \frac{54}{55}   \times  \frac{9}{3}  =  \frac{54 \times 9}{55 \times 3}  =  \frac{486}{165}

 \frac{486}{165}  =  \frac{162}{55}

5)

 \frac{42}{3}  +  \frac{12}{3}  =  \frac{42 \times 3 + 3 \times 12}{3 \times 3}  =  \frac{126 + 36}{9}

 \frac{162}{9}  =  \frac{18}{1}

6)

 \frac{18}{11}  \times  \frac{5}{3}  =  \frac{18 \times 5}{11 \times 3}  =  \frac{54}{55}

7)

 \frac{42}{3}  \div  \frac{12}{3}  =  \frac{3 \times 12}{42 \times 3}  =  \frac{126}{36} =  \frac{7}{2}

8)

 \frac{7}{10}  -  \frac{6}{2}  +  \frac{9}{3}  =  \frac{2 \times 7 - 10 \times 6}{10 + 2}  =  \frac{14 - 60}{20}

 \frac{ - 46}{20}   +  \frac{9}{3}  =  \frac{ - 46 \times 3 + 20 \times 9}{20 \times 3}  =  \frac{ - 138 + 180}{60}

 \frac{42}{60}  =  \frac{7}{10}

9)

 \frac{8}{5}  -  \frac{6}{2}  +  \frac{12}{3}  =  \frac{2 \times 8 + 5 \times 6}{5 \times 2}  =  \frac{16 - 30}{10}

 \frac{ - 14}{10}   +  \frac{12}{3}  =  \frac{ - 42 + 120}{30}  =  \frac{78}{30}  =  \frac{15}{5}

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