Question

logaritmacion, con propiedades

㏒² x + ㏒ ײ = 8

Answer 1

$log^{2}x + 2 logx = 8 \\ log ^{2} x + 2 logx - 8 = 0 \\ (log(x) + 4)( logx - 2 ) = 0 \\ igualando \: cada \: factor \: a \: cero\\ x = 10 ^{ - 4 } \\ x = 10 ^{ 2}$