Question

log⁷ ( x² - 2x - 2) = 0​

Answer 1

Explicación paso a paso:

$log( {( {x}^{2} - 2x - 2) }^{7} ) = 0 \\ { ({x }^{2} - 2x - 2)}^{7} = {10}^{0} \\ ( { {x}^{2} - 2x - 2) }^{7} = 1 \\ \sqrt[7]{ {( {x}^{2} - 2x - 2)}^{7} } = \sqrt[7]{1} \\ {x}^{2} - 2x - 2 = 1 \\ {x}^{2} - 2x - 2 - 1 = 0 \\ {x}^{2} - 2x - 3 = 0 \\ (x - 3)(x + 1) = 0 \\ (x - 3) = 0 \: \: \: \: (x + 1) = 0 \\ x = 0 + 3 \: \: \\ x = 0 - 1 \\ x = 3 \: o \: \: \: x = - 1$