Question

log6 (X)+log6 (X-5)=1

Answer 1

$Log_{6} x + Log_{x}(x-5) = 1$

$Log_{6} x + Log_{x}(x-5) = Log_{6} 6$

$Log_{6}[ x(x-5)]= Log_{6} 6$

x(x-5) = 6

$x^{2} -5x = 6$

$x^{2} -5x-6=0$
x                -6
x                +1

-6x + x = -5x

(x-6)(x+1) = 0

x - 6 = 0          x +1 = 0

x = 6                x = -1

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