Question

log5(2×+5)=log5(×+3)​

Answer 1

Respuesta:

$x=-2$

Explicación paso a paso:

$2\log _{10}\left(5\right)x+5\log _{10}\left(5\right)=\log _{10}\left(5\right)x+3\log _{10}\left(5\right)$

$2\log _{10}\left(5\right)x+5\log _{10}\left(5\right)-5\log _{10}\left(5\right)=\log _{10}\left(5\right)x+3\log _{10}\left(5\right)-5\log _{10}\left(5\right)$

$2\log _{10}\left(5\right)x=\log _{10}\left(5\right)x-2\log _{10}\left(5\right)$

$2\log _{10}\left(5\right)x-\log _{10}\left(5\right)x=\log _{10}\left(5\right)x-2\log _{10}\left(5\right)-\log _{10}\left(5\right)x$

$\log _{10}\left(5\right)x=-2\log _{10}\left(5\right)$

$\frac{\log _{10}\left(5\right)x}{\log _{10}\left(5\right)}=\frac{-2\log _{10}\left(5\right)}{\log _{10}\left(5\right)}$

$x=-2$