Question

Log2(x2-5x-4) =1
quien me ayuda ​

Answer 1

$Log_{2} (x^{2} - 5x - 4) = 1\\\\2^{1} = x^{2} - 5x - 4\\\\2 = x^{2} - 5x - 4$

0 = x² - 5x - 4 - 2

0 = x² - 5x -  6

      x          - 6

      x          + 1

- 6x + x = - 5x

(x - 6)(x + 1) = 0

x - 6 = 0         x + 1 = 0

x = 6               x  =  -1

Eternamente axllxa