Question

Log₂ (x + 1) + log₂ (x - 1) = log₂ 8
cómo se resuelve
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Answer 1

Respuesta:

3

Explicación paso a paso:

$log_{2}(x + 1) + log_{2}(x - 1) = log_{2}(8) \\ \\ log_{2}((x + 1)(x - 1)) = log_{2}(8) \\ \\ (x + 1)(x - 1) = 8 \\ \\ {x}^{2} - 1 = 8 \\ \\ {x}^{2} = 8 + 1 \\ \\ {x}^{2} = 9 \\ \\ x = 3$