Question

log2 8^x/log2 1/4=1/2

Answer 1

Teniendo en cuenta que: $log_b x^n = nlog_b x \ \ y \ \ log_b(b) = 1 :$

$\frac{log_2 {8^x}}{log_2 (1/4)} = \frac{1}{2} \\ \ \ x.log_2 (8) = \frac{1}{2} * log_2 (2^-2) \ \ x*(3) = (1/2)*(-2) \ \ \boxed{x = -1/3}$


Saludos!