Question

log2[6+log3(2x+1]=3

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Answer 1

Respuesta:

El valor de "x" es 4 ;)

Explicación paso a paso:

$log_{2}((6 + log_{3}(2x + 1) )) = 3 \\ log_{2}((6 + log_{3}(2x + 1) )) = log_{2}( {2}^{3} ) \\ 6 + log_{3}(2x + 1) = {2}^{3} \\ log_{3}(2x + 1) = log_{3}( {3}^{2} ) \\ 2x + 1 = {3}^{2} \\ x = 4$