Question

log(x+5)+log(2x+7)=1



Me ayudan????​

Answer 1

Respuesta:

Explicación paso a paso:

Answer 2

Respuesta:

Log(x+5)+log(2x+7) = 1

Log((x+5)(2x+7)) = 1 ; (x+5)(2x+7) = ((x+5)(2x+7)) = x(2x+7)+5(2x+7) = 2x²+7x+10x+35 = 2x²+17x+35

Log(2x²+17x+35) = 1

10^(Log(2x²+17x+35)) = 10^(1)

2x²+17x+35 = 10

2x²+17x+35-10 = 10-10

2x²+17x+25 = 0

x = (-(17)+-√((17)²-4(2)(25)))/(2×2)

x = ( -17+- √((289)-8(25))/4

x = ( -17+-√(289-200))/4

x = (-17+-√(89))/4

x1 = (-17-√(89))/4

x1 = -6,6085 ( Aproximadamente )

x2 = (-17+√(89))/4

x2 = -1,8915 ( Aproximadamente )

Explicación paso a paso: