Question

log(x-1)+ logx = log10

porfa ayudenme ... doy 20 pnts

Answer 1

Aplicando propiedades de potencias

        log(x - 1)*x = log10

             (x - 1)*x = 1
             x^2 - x = 1
             x^2 - x - 1 = 0
                                         Aplicando fórmula resolutiva
                                           x = (- b +/- √Δ)/2a
                                                     Δ = b^2 - 4.a.c
                                                         = (- 1)^2 - 4(1)(- 1)
                                                         = 5
                                           x = (1 +/- √5)/2.1
                                           x1 = (1 - √5)/2
                                           x2 = (1 + √5)/2
x no puede ser negativo

                                                  x = (1 + √5)/2  RESULTADO FINAL