Question

log (7x+1)=2 log (x+3)-log 2

Answer 1

Respuesta:

Aplicamos propiedades operacionales de logaritmos

log(7x + 1) + log2 = 2 log(x + 3)

log(7x + 1).2 = 2 log(x + 3)

log(7x + 1) = log(x + 3) 2 simplifica con 2

7x + 1 = x + 3

7x - x = 3 - 1

6x = 2

x = 2/6

x = 1/3 resultado final