Question

Log √60 3x+ log √60 5x=2
Con procedimiento por favor!

Answer 1

Respuesta:

x=2

Explicación paso a paso:

$log_{n}(a) + log_{n}(b) = log_{n}(a \times b)$

Entonces:

$log_{ \sqrt{60} }(3x) + log_{60}(5x) = 2 \\ log_{ \sqrt{60} }(3x \times 5x) = 2 \\ log_{ \sqrt{60} }(15 {x}^{2} ) = 2 \\ 15 {x}^{2} = \sqrt{60} ^{2} \\ 15 {x}^{2} = 60 \\ {x}^{2} = \frac{60}{15} \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = 2$