Question

log(32+x²) - 2.log(4-x) = 0 - ola buenas noches. alguien me ayuda a resolver este ejercicio urgente ​

Answer 1

Explicación paso a paso:

$log(32 + x {}^{2} ) - 2 log(4 - x ) = 0$

$log(32 + x {}^{2} ) {}^{ - 2} - 2 log(4 - x {}^{ } ) {}^{ - 2} = 0$

$log((32 + x {}^{2} ) \times \frac{1}{(4 - x) { }^{2} } ) = 0$

$log( \frac{32 - x {}^{2} }{(4 - x) {}^{2} } ) = 0$

$\frac{32 - x {}^{2} }{(4 - x) {}^{2} } = 1$

32-x²=(4-x)²

32-x²=16-8x+x²

-16+32=-8x

16=-8x

-2=x