Question

Log(10) 100 + log (2) 128 - log(5) 625 =

Answer 1

$log_{10}100 + log_{2}128- log_{5}625 \\ log_{10}{10}^{2} + log_{2} {2}^{7} - log_{5} {5}^{4 } \\ 2 log_{10}10 + 7 log_{2}2 - 4 log_{5}5 \\2 + 7 - 4 \\ 9 - 4 \\ 5$