Question

lo necesito para hoy! por fa​

Answer 1

Primer renglón:

$a=-4$

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$a-2b^{3} =50\\-4-2b^{3} =50\\-2b^{3} =50+4\\-2b^{3} =54\\b^{3} =-\frac{54}{2}\\b^{3} =-27\\b=\sqrt[3]{-27}\\b=-3$

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$-2a+b=x\\-2(-4)+(-3)=x\\8-3=x\\x= 5\\-2a+b=5$

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$-3a^{2} =x\\-3(-4)^{2} =x\\-3(16)=x\\x=-48\\-3a^{2}=-48$

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$a-2b^{3} =50$

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Segundo renglón:

$-2a+b=8\\-2a+4=8\\-2a=8-4\\-2a=4\\a=-\frac{4}{2} \\a=-2$

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$b=4$

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$-2a+b=8$

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$-3a^{2}=x\\-3(-2)^{2} =x\\-3(4)=x\\x=-12\\-3a^{2}=-12$

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$a-2b^{3}=x\\(-2)-2(4)^{3}=x\\-2-2(64)=x\\-2-128=x\\x=-130\\a-2b^{3} =-130$

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Tercer renglón

$a-2b^{3} =-7\\a-2(-1)^{3}=-7\\a-2(-1)=-7\\a-(-2)=-7 \\a+2=-7\\a=-7-2\\a=-9$

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$b=-1$

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$-2a+b=x\\-2(-9)+(-1)=x\\18+(-1)=x\\x=18-1\\x=17\\-2a+b=17$

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$-3a^{2}=x\\-3(-9)^{2} =x \\-3(81)=x\\-243=x\\-3a^{2} =-243$

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$a-2b^{3} =-7$