Question

Llevo 5 horas estresandome con esta tarea, tengo la cordura -100​

Answer 1

Respuesta:

1)

$\frac{4a^3-50ab^2-6a^2b^3}{-2a}\\\\\\\frac{2a\left(2a^2-25b^2-3ab^3\right)}{-2a}\\\\\\\frac{a\left(2a^2-25b^2-3ab^3\right)}{-a}\\\\\\\frac{2a^2-25b^2-3ab^3}{-1}\\\\\\-\left(2a^2-25b^2-3ab^3\right)\\\\\\-2a^2+25b^2+3ab^3$

2)

$\frac{4x^8-10x^6-5x^4}{2x^3}\\\\\\\frac{x^4\left(4x^4-10x^2-5\right)}{2x^3}\\\\\\\frac{x^3x\left(4x^4-10x^2-5\right)}{2x^3}\\\\\\\frac{x\left(4x^4-10x^2-5\right)}{2}$

3)

$\frac{m^2+11m+30}{m+6}\\\\\\\frac{\left(m+5\right)\left(m+6\right)}{m+6}\\\\\\m+5$

4)

$\frac{m^5+3m^2-6-2m^4}{m+1}\\\\\\m^4+\frac{-3m^4+3m^2-6}{m+1}\\\\\\m^4-3m^3+\frac{3m^3+3m^2-6}{m+1}\\\\\\m^4-3m^3+3m^2+\frac{-6}{m+1}\\\\\\m^4-3m^3+3m^2-\frac{6}{m+1}$