Question

\lim _{x\to 0}\frac{5x^3+8x^2}{3x^4-16x^2}

Answer 1

$\huge\red {\mid {\fbox{\tt {Hola}}\mid}}$

5x^3+8x^2/3x^4-16x^2

=8/3x^6+5x^3−16x^2