La tostación de la pirita se produce según la reacción: 4fes 2 + 11o 2 – 2fe 2 o3 +8so 2 calcule:
a.la cantidad de fe 2 o 3 que se obtiene al tratar 500 kg de pirita de un 92 % de riqueza en fes 2 , con exceso de oxígeno.
b.el volumen de oxígeno, medido a 20 ºc y 720 mm de hg, necesario para tostar los 500 kg de pirita del 92 % de riqueza. datos: r = 0’082 atm·l·k -1 ·mol -1 . masas atómicas: fe = 56; s = 32; o = 16 .
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4FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
Mm FeS2 (Pirirta) = 120 g/mol
Fe2O3 = 160 g/mol
a) calcular gramos de Fe2O3
1 Kg ----- 1000 g
500 Kg ------ x
x = 500000 g FeS2
g Fe2O3=500000 g FeS2 x 1mol FeS2 x 2 mol Fe2O3 x 160 g x 92 g
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120 g FeS2 4 mol FeS2 1 mol 100 g
g = 306.667 g de Fe2O3
B) Aplicar Ley de los Gases Ideales
V x P = n x R x T
R = 0.082 (L atm /mol K)
T = 20 ºC + 273 = 293 K
P = 720 mmHg / 760 = 0.94736 atm
n = ?
calcular moles de O2
moles O2 = 500000 g FeS2 x 1 mol FeS2 x 11 mol O2 x 92 g
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120 g FeS2 4 mol FeS2 100 g
moles O2 = 10541.66
calcular V(L) de oxígeno
V = 10541.66 moles x 0.082 (L atm / mol K) x 293 K
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0.94736 atm
V = 267344.69 L
Mm FeS2 (Pirirta) = 120 g/mol
Fe2O3 = 160 g/mol
a) calcular gramos de Fe2O3
1 Kg ----- 1000 g
500 Kg ------ x
x = 500000 g FeS2
g Fe2O3=500000 g FeS2 x 1mol FeS2 x 2 mol Fe2O3 x 160 g x 92 g
```````````````` ````````````````` `````````` ````````
120 g FeS2 4 mol FeS2 1 mol 100 g
g = 306.667 g de Fe2O3
B) Aplicar Ley de los Gases Ideales
V x P = n x R x T
R = 0.082 (L atm /mol K)
T = 20 ºC + 273 = 293 K
P = 720 mmHg / 760 = 0.94736 atm
n = ?
calcular moles de O2
moles O2 = 500000 g FeS2 x 1 mol FeS2 x 11 mol O2 x 92 g
````````````````` ``````````````` ````````
120 g FeS2 4 mol FeS2 100 g
moles O2 = 10541.66
calcular V(L) de oxígeno
V = 10541.66 moles x 0.082 (L atm / mol K) x 293 K
````````````````````````````````````````````````````````````````````
0.94736 atm
V = 267344.69 L
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