Question

la solucion de 16x-[3x-(6-9x)]=30x+[-(3x+2)-(x+3)]

Answer 1

Respuesta:

16x-[3x-(6-9x)]=30x+[-(3x+2)-(x+3)]

16x-[3x-6+9x]=30x+[-3x-2-x-3]

16x-[12x-6]=30x+[-4x-5]

16x-12x+6 = 30x-4x-5

4x + 6 = 26x - 5

6+5 = 26x - 4x

11 = 22x

11/22 = x

1/2 = x

Explicación paso a paso:

Answer 2

Respuesta:

x = 1/2

Explicación paso a paso:

16x-[3x-(6-9x)]=30x+[-(3x+2)-(x+3)]

16x-[3x-6+9x]=30x+[-3x-2-x-3]

16x-[12x-6]=30x+[-4x-5]

16x-12x+6=30x-4x-5

4x + 6 = 26x - 5 => 11 = 22x => x = 1/2

Comprobación:

16(1/2) - [3(1/2) - (6 - 9(1/2))] = 30(1/2) + [-(3(1/2) + 2) - (1/2 + 3)]

8 - [3/2 - (12/2 - 9/2)] = 15 + [-(3/2 + 4/2) - (1/2 + 6/2)]

8 - [3/2 - (3/2)] = 15 + [-(7/2) - (7/2)]

8 = 15 + [-7] => 8 = 8

RPTA: x = 1/2