Question

la segunda ,la tercera y la cuarta porfa

Answer 1

Respuesta:

no se nada

Explicación paso a paso:

Answer 2

2_ A

$\sqrt{ \frac{16}{25} } \\ \sqrt{16} = \sqrt4 ^{2} \\ \sqrt{25} = \sqrt 5 ^{2} \\ \sqrt{4 ^{2} } = 4 \\ \sqrt{5^{2} } = 5 \\ = \frac{4}{5}$

B

$\sqrt[3] \frac{27}{64} \\ \sqrt[3]{27} = \sqrt[3]{3 ^{3} } \\ \sqrt[3]{64} = \sqrt[3]{4 ^{3} } \\ \sqrt[ 3]{3 ^{3} } = 3 \\ \sqrt[3]{4 ^{3} } = 4 \\ \frac{3}{4}$

3_

$( \frac{9}{16} \times \frac{25}{36} \times \frac{64}{100} )^{ \frac{1}{2} } \\ (9 \times \frac{25}{36} \times \frac{4}{100} ) ^{ \frac{1}{2} } \\ ( \frac{25}{4} \times \frac{4}{100}) ^{ \frac{1}{2}} \\ ( \frac{1}{4} \times \frac{4}{4} ) ^{ \frac{1}{2}} \\ ( \frac{1}{4})^{ \frac{1}{2}} \\ \sqrt{ \frac{1}{4} } = \frac{1}{2}$

4_