La reacción de la hidracina (N2H2) con el oxígeno (O4) es la siguiente:
N2H2+O2→H2O+N2
Se hace reaccionar 4,8 moles de hidracina (N2H2) en exceso de O2 y al finalizar la reacción se produjeron 64,8 g de H2O. Determine el rendimiento de la reacción. (Dato: P.A: H=1, O=16).
soluciones
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Respuesta:
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