la formula empirica del compuesto es ch si la masa molar , alguien sabe
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FE: CH
Mm CH
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
``````````````````````````
Mm = 13 g/mol
n = 78 g/mol / 13 g/mol
n = 6
FM: (CH)n = (CH)6 = C6H6 (BENCENO)
Mm CH
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
``````````````````````````
Mm = 13 g/mol
n = 78 g/mol / 13 g/mol
n = 6
FM: (CH)n = (CH)6 = C6H6 (BENCENO)
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