Question

la distancia y el desplazamiento son sinonimos ¿porque?​

Answer 1

Explicación:

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${0y0}^{?} \times {( { = > .5 < \sqrt[x10y1.8 < {y25 > = 2 {621}^{?} }^{?} \times \frac{?}{?} \times \frac{?}{?} ]{?} }^{2} \times \frac{?}{?} }^{?} \frac{?}{?} 0 |21y = < 0 {xx \frac{15.2255221125 {254 { \frac{ {2.3 < > 2. - + \times 52 = 96 \leqslant \leqslant \times + 2 \frac{.1. < t}{?} \times \frac{?}{?} }^{?} }fdr \gamma log_{ \beta \sec(?) }(?) {?} }^{?} }^{?} }{?} }^{2} |$

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