Question

la diagonal mayor de un rombo mide 27 cm y la menor 2/3 de la mayor.hallar su área​

Answer 1

Respuesta:

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Answer 2

DIAGONAL MAYOR =  27 cm

DIAGONAL MENOR =  $\frac{2}{3}(27) = \frac{54}{3} = 18$

Área del Rombo

$A = \frac{D.d}{2}\\ \\A = \frac{(27)(18)}{2} \\\\A = \frac{486}{2}\\ \\A = 243 cm^{2}$

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