If a trapezoid is largest base is 12m and the smallest bad is 5 and the height is 10 what's the area
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Respuesta:Subtract the parallelogram with bases of 10 and the same altitude. You will be left with a triangle base 5 and sides 3 and 4.
Sqrt(3^2 - x^2) = h
Sqrt(4^2 - [5 - x]^2) = h
= sqrt(16 - 25 + 10x - x^2)
= sqrt(-x^2 + 10x - 9)
Sqrt(9 - x^2) = sqrt(-x^2 + 10x - 9)
Square both sides
9 - x^2 = -x^2 + 10x - 9
10x = 18; x= 9/5
h = sqrt(9 - 81/25) = sqrt([225 - 81]/25)
h = sqrt(144/25) = 12/5 = 2.4
Height is equal to 2.4 units.
A = 2.4(10 + 15)/2 = 30 square units
The area of the trapezoid is 30 square units.
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Sqrt(3^2 - x^2) = h
Sqrt(4^2 - [5 - x]^2) = h
= sqrt(16 - 25 + 10x - x^2)
= sqrt(-x^2 + 10x - 9)
Sqrt(9 - x^2) = sqrt(-x^2 + 10x - 9)
Square both sides
9 - x^2 = -x^2 + 10x - 9
10x = 18; x= 9/5
h = sqrt(9 - 81/25) = sqrt([225 - 81]/25)
h = sqrt(144/25) = 12/5 = 2.4
Height is equal to 2.4 units.
A = 2.4(10 + 15)/2 = 30 square units
The area of the trapezoid is 30 square units.