Question

How many moles of saccharose are present in 320 g or saccharose C12H22O11?

a) 0.9352 moles
b) 1.9352 moles
c) 0.9352 moles
d) 0.9352 g

Answer 1

Respuesta:

n = 0.9356 de sacarosa

Explicación:

How many moles of saccharose are present in 320 g or saccharose C12H22O11?

a) 0.9352 moles

b) 1.9352 moles

c) 0.9352 moles

d) 0.9352 g

datos:

Mm sacarosa = 342 g/mol

m sacarosa = 320 g

n ( sacarosa) = ¿?

calcular moles de sacarosa

n = 320 g C12H22O11  x  1 mol C12H22O11

                                         342 g C12H22O11

n = 0.9356 de sacarosa