Question

Holii Porfi ayudenme

Answer 1

x³+x²+5x+5= x²×(x+1)+5(x+1)=(x+1)×(x²+5)

3x²-6+x³-2x= 3(x²-2)+x×(x²-2)=(x²-2)×(3+x)

2x⁴+6-x⁵-3x= 2(x⁴+3)-x×(x⁴+3)=(x⁴+3)×(2-x)