Question

HOLA POR FAVOR AYUDENME

Answer 1

RESOLUCIÓN:

$T1 = \frac{ \sqrt[]{3} }{5} {a}^{ \frac{x}{3} + 1 } {b}^{12} \\ T2 = - \frac{6}{5} {b}^{3(y - 7) {a}^{5} }$

${a}^{ \frac{x}{3} + 1} = {a}^{5} \\ \frac{x}{3} + 1 = 5 \\ \frac{x}{3} = 5 - 1 \\ \frac{x}{3} = 4 \\ x = 4 \times 3 \\ x = 12$

${b}^{3(y - 7)} = {b}^{12} \\ 3(y - 7) = 12 \\ 3y - 21 = 12 \\ 3y = 12 + 21 \\ 3y = 33 \\ y = \frac{33}{3} \\ y = 11$

RESPUESTA:

X - Y = 12 - 11 = 1

Answer 2

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