Question

Hola , por favor ayuden con el desarrollo del siguiente caso

Answer 1

$P(x) = x^3-10000x^2-10002x+9999\\\\ P(x)=x^2(x-10000)-10002x+9999\\\\ P(x)=x^2(100001-10000)-10002x+9999\\\\ P(x)=x^2-10002x+9999\\\\ P(x)=x(x-10002)+9999\\\\ P(x)=x(10001-10002)+9999\\\\ P(x)=-x+9999\\\\ P(10001)=-10001+9999\\\\ P(10001)=-2$