Question

Hola podria alguien resolver estas ecuaciónes?
1) 2x-10=-29-3
2) 6x+77= -40
3) 2(x-3)-7=3 (1-2x)

Answer 1

Explicación paso a paso:

$1) \\ 2x - 10 = - 29 - 3 \\2x - 10 = - 32 \\ 2x = - 32 + 10 \\ 2x = - 22 \\ x = - 22 \div 2 \\ x = - 11 \\ \\ comprobacion \\ 2 \times ( - 11) - 10 = - 29 - 3 \\ - 22 - 10 = - 32 \\ - 32 = - 32\\ \\ 2) \\ 6x + 77 = - 40 \\6x = - 40 - 77 \\ 6x = - 117 \\ x = - \frac{117}{6} \\ \\comprobamos \\ 6 \times ( - \frac{ 117}{6}) + 77 = - 40 \\ \\ - \frac{702}{6} + 77 = - 40\\ \\ - 117 + 77 = - 40 \\ - 40 = - 40 \\ \\ 3) \\ 2(x - 3) - 7 = 3(1 - 2x) \\ 2x - 6 - 7 = 3 - 6x \\ 2x - 13 = 3 - 6x \\ 2x + 6x = 3 + 13 \\ 8x = 16 \\ x = \frac{16}{8} \\ \\ x = 2 \\ \\ comprobacion \\ 2(2 - 3) - 7 = 3(1 - 2 \times 2) \\ 2( - 1) - 7 = 3(1 - 4) \\ - 2 - 7 = 3( - 3) \\ - 9 = - 9$