Question

hola me pueden ayudar porfavor se los agradecería un montón ​

Answer 1

Explicación paso a paso:

1)

$2\cdot \:11^1-6^3-5^3\sqrt{125}+8^0\\\\\\=2\cdot \:11^1-6^3-5^3\sqrt{125}+1\\\\\\=2\cdot \:11-6^3-5^3\sqrt{125}+1\\\\\\=22-6^3-5^4\sqrt{5}+1\\\\\\=23-5^4\sqrt{5}-6^3\\\\\\=23-625\sqrt{5}-6^3\\\\\\=23-625\sqrt{5}-216\\\\\\=-193-625\sqrt{5}$

2)

$2x\left(4-1\right)^2+18\%\:2^3+2^0\\\\\\=2x\left(4-1\right)^2+\frac{9}{50}\cdot \:2^3+2^0\\\\\\=2\left(4-1\right)^2x+2^3\cdot \frac{9}{50}+1\\\\\\=3^2\cdot \:2x+\frac{36}{25}+1\\\\\\=\frac{1\cdot \:25}{25}+\frac{36}{25}\\\\\\=\frac{1\cdot \:25+36}{25}\\\\\\=3^2\cdot \:2x+\frac{61}{25}\\\\\\=18x+\frac{61}{25}$

3)

$\left(1+2\right)^3\%\:\sqrt{9}-\sqrt{18+23}\\\\\\=\frac{27}{100}\sqrt{9}-\sqrt{18+23}\\\\\\=\frac{81}{100}-\sqrt{41}$

Answer 2

Respuesta:

una pregunta que tema es.

para ayudarte mejor