Question

hola me ayudan por favor a resolver esta actividad ​

Answer 1

Explicación paso a paso:

${h}^{2} = {c.a}^{2} + {c.o}^{2}$

${x}^{2} = {3}^{2} + {4}^{2} \\ {x}^{2} = 9 + 16 \\ {x}^{2} = 25 \\ {x}^{2} = \sqrt{25} \\ x = 5$

${x}^{2} = {24}^{2} + {7}^{2} \\ {x}^{2} = 576 + 49 \\ {x}^{2} = 625 \\ {x}^{2} = \sqrt{625} \\ x = 25$

${17}^{2} = {a}^{2} + {15}^{2} \\ 289 = {a}^{2} + 225 \\ 289 - 225 = {a}^{2} \\ 64 = {a}^{2} \\ a = \sqrt{64} \\ a = 8$

${7}^{2} = {5}^{2} + {r}^{2} \\ 49 = 25 + {r}^{2} \\ 49 - 25 = {r}^{2} \\ 24 = {r}^{2} \\ r = \sqrt{24}$

${y}^{2} = {40}^{2} + {9}^{2} \\ {y}^{2} = 1600 + 81 \\ {y}^{2} = 1681 \\ y = \sqrt{1681} \\ y = 41$

${b}^{2} = {6}^{2} + {8}^{2} \\ {b}^{2} = 36 + 64 \\ {b}^{2} = 100 \\ b = \sqrt{100} \\ b = 10$