Question

hayar El Factor Comun
*9b²-30a²b+25a⁴
*9m²n²+42mn+49
*a⁶b⁶
*16x⁹-196x
*36a⁸-100b⁸​

Answer 1

$9b²-30a²b+25a⁴$

Por aspa simple

$(3b - 5 {a}^{2} )(3b - 5 {a}^{2} )$

${(3b - 5 {a}^{2} )}^{2}$

9m²n²+42mn+49

$9m²n²+42mn+49$

Es un trinomio cuadrado perfecto

$(3mn + 7)(3mn + 7) = ( {3mn + 7})^{2}$

a⁶b⁶

$a⁶b⁶ = ab( {a}^{5} {b}^{5} )$

16x⁹-196x

$16x⁹-196x = 4x(4 {x}^{8} - 49)$

$4x( {2}^{2} {x}^{8} - {7}^{2} )$

$4x(2 {x}^{4} - 7)(2 {x}^{4} + 7)$

36a⁸-100b⁸

$36a⁸-100b⁸$

${6}^{2} {a}^{8} - {10}^{2} {b}^{8}$

Por diferencia de cuadrados

$(6 {a}^{4} + 10 {b}^{4} )(6 {a}^{4} - 10 {b}^{4} )$